10 questions · Form 5 Additional Mathematics Bab 1: Circular Measure
A sector has an area of 50 cm² and a radius of 10 cm. Find the arc length of the sector.
Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. A sector has an area of 50 cm² and a radius of 10 cm. Find the arc length of the sector.
Answer: A
A = 12 r s => 50 = 12 (10) s => 50 = 5s => s = 10 cm.
2. The minor arc AB of a circle with centre O and radius 7 cm has a length of 11 cm. Find the major angle AOB in radians. (Take π = 3.142)
Answer: A
Minor angle θ = sr = 117 = 1.571 rad. Major angle = 2π - 1.571 = 2(3.142) - 1.571 = 6.284 - 1.571 = 4.713 rad.
3. A sector of a circle has a radius of 6 cm and an area of 27 cm². Find the central angle subtended in radians.
Answer: A
Area A = 12 r² θ => 27 = 12 (6²) θ => 27 = 18θ => θ = 2718 = 1.5 rad.
4. An arc length of 15 cm subtends an angle of 1.5 rad at the centre of a circle. What is the radius of the circle?
Answer: A
s = rθ => 15 = r(1.5) => r = 151.5 = 10 cm.
5. Find the perimeter of a sector with a radius of 10 cm and a central angle of 0.8 rad.
Answer: B
Arc length s = rθ = 10 × 0.8 = 8 cm. Perimeter = s + 2r = 8 + 2(10) = 28 cm.
6. If the arc length of a circle is equal to twice its radius, what is the central angle in radians?
Answer: D
s = rθ => 2r = rθ => θ = 2.0 rad.
7. Find the area of the minor segment subtended by an angle of π3 rad in a circle of radius 6 cm.
Answer: B
Sector area = 12 (6²) (π3) = 6π ≈ 18.85 cm². Triangle area = 12 (6²) sin(60°) = 18 × (√32) ≈ 15.59 cm². Segment area = 18.85 - 15.59 = 3.26 cm².
8. The perimeter of a sector of a circle of radius r cm is 25 cm. If the angle at the centre is 1.5 rad, find the value of r.
Answer: D
Perimeter = rθ + 2r = r(θ + 2). 25 = r(1.5 + 2) => 25 = 3.5r => r = 253.5 = 7.14 cm.
9. Convert 5π6 radians to degrees.
Answer: B
(5π6) × (180°/π) = 5 × 30° = 150°.
10. A wheel rotates through 15 complete revolutions. What is the total angle rotated in radians?
Answer: B
1 revolution = 2π rad. 15 revolutions = 15 × 2π = 30π rad.